2(x+1)+4x=3(2x-1)+8

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Solution for 2(x+1)+4x=3(2x-1)+8 equation: 


Simplifying
2(x + 1) + 4x = 3(2x + -1) + 8

Reorder the terms:
2(1 + x) + 4x = 3(2x + -1) + 8
(1 * 2 + x * 2) + 4x = 3(2x + -1) + 8
(2 + 2x) + 4x = 3(2x + -1) + 8

Combine like terms: 2x + 4x = 6x
2 + 6x = 3(2x + -1) + 8

Reorder the terms:
2 + 6x = 3(-1 + 2x) + 8
2 + 6x = (-1 * 3 + 2x * 3) + 8
2 + 6x = (-3 + 6x) + 8

Reorder the terms:
2 + 6x = -3 + 8 + 6x

Combine like terms: -3 + 8 = 5
2 + 6x = 5 + 6x

Add '-6x' to each side of the equation.
2 + 6x + -6x = 5 + 6x + -6x

Combine like terms: 6x + -6x = 0
2 + 0 = 5 + 6x + -6x
2 = 5 + 6x + -6x

Combine like terms: 6x + -6x = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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