2(x+1)+4x=6(x+3)

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Solution for 2(x+1)+4x=6(x+3) equation: 



2(x+1)+4x=6(x+3)

We move all terms to the left:

2(x+1)+4x-(6(x+3))=0

We add all the numbers together, and all the variables

4x+2(x+1)-(6(x+3))=0

We multiply parentheses

4x+2x-(6(x+3))+2=0



We calculate terms in parentheses: -(6(x+3)), so:

6(x+3)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We add all the numbers together, and all the variables

6x-(6x+18)+2=0

We get rid of parentheses

6x-6x-18+2=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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