2(x+1)+5(3x+4)=10x+22

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Solution for 2(x+1)+5(3x+4)=10x+22 equation: 



2(x+1)+5(3x+4)=10x+22

We move all terms to the left:

2(x+1)+5(3x+4)-(10x+22)=0

We multiply parentheses

2x+15x-(10x+22)+2+20=0

We get rid of parentheses

2x+15x-10x-22+2+20=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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