2(x+1)+5=(3x+3x)-x+1

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Solution for 2(x+1)+5=(3x+3x)-x+1 equation: 



2(x+1)+5=(3x+3x)-x+1

We move all terms to the left:

2(x+1)+5-((3x+3x)-x+1)=0

We add all the numbers together, and all the variables

2(x+1)-((+6x)-x+1)+5=0

We multiply parentheses

2x-((+6x)-x+1)+2+5=0



We calculate terms in parentheses: -((+6x)-x+1), so:

(+6x)-x+1

We add all the numbers together, and all the variables

-1x+(+6x)+1

We get rid of parentheses

-1x+6x+1

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We add all the numbers together, and all the variables

2x-(5x+1)+7=0

We get rid of parentheses

2x-5x-1+7=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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