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2(x+1)+6=20-3(x)x=4
We move all terms to the left:
2(x+1)+6-(20-3(x)x)=0
We add all the numbers together, and all the variables
2(x+1)-(-3xx+20)+6=0
We multiply parentheses
2x-(-3xx+20)+2+6=0
We get rid of parentheses
2x+3xx-20+2+6=0
We add all the numbers together, and all the variables
2x+3xx-12=0
We move all terms containing x to the left, all other terms to the right
2x+3xx=12
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