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2(x+1)+6=5x-3(-2+x)
We move all terms to the left:
2(x+1)+6-(5x-3(-2+x))=0
We add all the numbers together, and all the variables
2(x+1)-(5x-3(x-2))+6=0
We multiply parentheses
2x-(5x-3(x-2))+2+6=0
We calculate terms in parentheses: -(5x-3(x-2)), so:We add all the numbers together, and all the variables
5x-3(x-2)
We multiply parentheses
5x-3x+6
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
2x-(2x+6)+8=0
We get rid of parentheses
2x-2x-6+8=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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