2(x+1)+x+1=4(x+1)-5

Solution for 2(x+1)+x+1=4(x+1)-5 equation:

2(x+1)+x+1=4(x+1)-5

We move all terms to the left:

2(x+1)+x+1-(4(x+1)-5)=0

We add all the numbers together, and all the variables

x+2(x+1)-(4(x+1)-5)+1=0

We multiply parentheses

x+2x-(4(x+1)-5)+2+1=0


We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)


We add all the numbers together, and all the variables

3x-(4x-1)+3=0

We get rid of parentheses

3x-4x+1+3=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4