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2(x+1)-1=5x-3(-2x+x)
We move all terms to the left:
2(x+1)-1-(5x-3(-2x+x))=0
We add all the numbers together, and all the variables
2(x+1)-(5x-3(-1x))-1=0
We multiply parentheses
2x-(5x-3(-1x))+2-1=0
We calculate terms in parentheses: -(5x-3(-1x)), so:We add all the numbers together, and all the variables
5x-3(-1x)
We multiply parentheses
5x+3x
We add all the numbers together, and all the variables
8x
Back to the equation:
-(8x)
-6x+1=0
We move all terms containing x to the left, all other terms to the right
-6x=-1
x=-1/-6
x=1/6
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