2(x+1)-3(2-x)=x+3(2x+1)

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Solution for 2(x+1)-3(2-x)=x+3(2x+1) equation: 



2(x+1)-3(2-x)=x+3(2x+1)

We move all terms to the left:

2(x+1)-3(2-x)-(x+3(2x+1))=0

We add all the numbers together, and all the variables

2(x+1)-3(-1x+2)-(x+3(2x+1))=0

We multiply parentheses

2x+3x-(x+3(2x+1))+2-6=0



We calculate terms in parentheses: -(x+3(2x+1)), so:

x+3(2x+1)

We multiply parentheses

x+6x+3

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We add all the numbers together, and all the variables

5x-(7x+3)-4=0

We get rid of parentheses

5x-7x-3-4=0

We add all the numbers together, and all the variables

-2x-7=0

We move all terms containing x to the left, all other terms to the right

-2x=7

x=7/-2

x=-3+1/2

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