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2(x+1)-3(2-x)=x+3(2x+1)
We move all terms to the left:
2(x+1)-3(2-x)-(x+3(2x+1))=0
We add all the numbers together, and all the variables
2(x+1)-3(-1x+2)-(x+3(2x+1))=0
We multiply parentheses
2x+3x-(x+3(2x+1))+2-6=0
We calculate terms in parentheses: -(x+3(2x+1)), so:We add all the numbers together, and all the variables
x+3(2x+1)
We multiply parentheses
x+6x+3
We add all the numbers together, and all the variables
7x+3
Back to the equation:
-(7x+3)
5x-(7x+3)-4=0
We get rid of parentheses
5x-7x-3-4=0
We add all the numbers together, and all the variables
-2x-7=0
We move all terms containing x to the left, all other terms to the right
-2x=7
x=7/-2
x=-3+1/2
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