2(x+1)-3(2x-4)=-3(-x+1)

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Solution for 2(x+1)-3(2x-4)=-3(-x+1) equation: 



2(x+1)-3(2x-4)=-3(-x+1)

We move all terms to the left:

2(x+1)-3(2x-4)-(-3(-x+1))=0

We add all the numbers together, and all the variables

2(x+1)-3(2x-4)-(-3(-1x+1))=0

We multiply parentheses

2x-6x-(-3(-1x+1))+2+12=0



We calculate terms in parentheses: -(-3(-1x+1)), so:

-3(-1x+1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

-4x-(3x-3)+14=0

We get rid of parentheses

-4x-3x+3+14=0

We add all the numbers together, and all the variables

-7x+17=0

We move all terms containing x to the left, all other terms to the right

-7x=-17

x=-17/-7

x=2+3/7

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