2(x+1)-3(x2)=x+6

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Solution for 2(x+1)-3(x2)=x+6 equation: 



2(x+1)-3(x2)=x+6

We move all terms to the left:

2(x+1)-3(x2)-(x+6)=0

We add all the numbers together, and all the variables

-3x^2+2(x+1)-(x+6)=0

We multiply parentheses

-3x^2+2x-(x+6)+2=0

We get rid of parentheses

-3x^2+2x-x-6+2=0

We add all the numbers together, and all the variables

-3x^2+x-4=0

a = -3; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-3)·(-4)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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