2(x+1)-3=3(x-2)+5

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Solution for 2(x+1)-3=3(x-2)+5 equation: 



2(x+1)-3=3(x-2)+5

We move all terms to the left:

2(x+1)-3-(3(x-2)+5)=0

We multiply parentheses

2x-(3(x-2)+5)+2-3=0



We calculate terms in parentheses: -(3(x-2)+5), so:

3(x-2)+5

We multiply parentheses

3x-6+5

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

2x-(3x-1)-1=0

We get rid of parentheses

2x-3x+1-1=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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