2(x+1)-7=3(x-5)+10

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Solution for 2(x+1)-7=3(x-5)+10 equation: 



2(x+1)-7=3(x-5)+10

We move all terms to the left:

2(x+1)-7-(3(x-5)+10)=0

We multiply parentheses

2x-(3(x-5)+10)+2-7=0



We calculate terms in parentheses: -(3(x-5)+10), so:

3(x-5)+10

We multiply parentheses

3x-15+10

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

2x-(3x-5)-5=0

We get rid of parentheses

2x-3x+5-5=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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