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2(x+1)-7=3(x-5)+10
We move all terms to the left:
2(x+1)-7-(3(x-5)+10)=0
We multiply parentheses
2x-(3(x-5)+10)+2-7=0
We calculate terms in parentheses: -(3(x-5)+10), so:We add all the numbers together, and all the variables
3(x-5)+10
We multiply parentheses
3x-15+10
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
2x-(3x-5)-5=0
We get rid of parentheses
2x-3x+5-5=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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