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2(x+1)-8=4x-2(x+3)
We move all terms to the left:
2(x+1)-8-(4x-2(x+3))=0
We multiply parentheses
2x-(4x-2(x+3))+2-8=0
We calculate terms in parentheses: -(4x-2(x+3)), so:We add all the numbers together, and all the variables
4x-2(x+3)
We multiply parentheses
4x-2x-6
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
2x-(2x-6)-6=0
We get rid of parentheses
2x-2x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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