2(x+1)-8=4x-2(x+3)

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Solution for 2(x+1)-8=4x-2(x+3) equation: 



2(x+1)-8=4x-2(x+3)

We move all terms to the left:

2(x+1)-8-(4x-2(x+3))=0

We multiply parentheses

2x-(4x-2(x+3))+2-8=0



We calculate terms in parentheses: -(4x-2(x+3)), so:

4x-2(x+3)

We multiply parentheses

4x-2x-6

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

2x-(2x-6)-6=0

We get rid of parentheses

2x-2x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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