2(x+1)=(21+3x)/2

Solution for 2(x+1)=(21+3x)/2 equation:

2(x+1)=(21+3x)/2

We move all terms to the left:

2(x+1)-((21+3x)/2)=0

We add all the numbers together, and all the variables

2(x+1)-((3x+21)/2)=0

We multiply parentheses

2x-((3x+21)/2)+2=0

We multiply all the terms by the denominator


2x*2)-((3x+21)+2*2)=0

We add all the numbers together, and all the variables

2x*2)-((3x+21)=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$