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2(x+1)=1/3(x-5)
We move all terms to the left:
2(x+1)-(1/3(x-5))=0
Domain of the equation: 3(x-5))!=0We multiply parentheses
x∈R
2x-(1/3(x-5))+2=0
We multiply all the terms by the denominator
2x*3(x-5))-(1+2*3(x-5))=0
Wy multiply elements
6x^2(x+6x(x=0
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