2(x+1)=1/3x+4

Solution for 2(x+1)=1/3x+4 equation:

2(x+1)=1/3x+4

We move all terms to the left:

2(x+1)-(1/3x+4)=0


Domain of the equation: 3x+4)!=0

x∈R


We multiply parentheses

2x-(1/3x+4)+2=0

We get rid of parentheses

2x-1/3x-4+2=0

We multiply all the terms by the denominator


2x*3x-4*3x+2*3x-1=0

Wy multiply elements

6x^2-12x+6x-1=0

We add all the numbers together, and all the variables

6x^2-6x-1=0

a = 6; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·6·(-1)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{15}}{2*6}=\frac{6-2\sqrt{15}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{15}}{2*6}=\frac{6+2\sqrt{15}}{12}
$