2(x+1)=28+2(x-2)

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Solution for 2(x+1)=28+2(x-2) equation: 



2(x+1)=28+2(x-2)

We move all terms to the left:

2(x+1)-(28+2(x-2))=0

We multiply parentheses

2x-(28+2(x-2))+2=0



We calculate terms in parentheses: -(28+2(x-2)), so:

28+2(x-2)

determiningTheFunctionDomain
2(x-2)+28

We multiply parentheses

2x-4+28

We add all the numbers together, and all the variables

2x+24

Back to the equation:

-(2x+24)



We get rid of parentheses

2x-2x-24+2=0

We add all the numbers together, and all the variables

-22!=0

There is no solution for this equation

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