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2(x+1)=3(1+2/3x
We move all terms to the left:
2(x+1)-(3(1+2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(x+1)-(3(2/3x+1)=0
We multiply parentheses
2x-(3(2/3x+1)+2=0
We multiply all the terms by the denominator
2x*3x+1)+2-(3(2=0
We add all the numbers together, and all the variables
2x*3x=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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