2(x+1)=3(x-4)+8

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Solution for 2(x+1)=3(x-4)+8 equation: 


Simplifying
2(x + 1) = 3(x + -4) + 8

Reorder the terms:
2(1 + x) = 3(x + -4) + 8
(1 * 2 + x * 2) = 3(x + -4) + 8
(2 + 2x) = 3(x + -4) + 8

Reorder the terms:
2 + 2x = 3(-4 + x) + 8
2 + 2x = (-4 * 3 + x * 3) + 8
2 + 2x = (-12 + 3x) + 8

Reorder the terms:
2 + 2x = -12 + 8 + 3x

Combine like terms: -12 + 8 = -4
2 + 2x = -4 + 3x

Solving
2 + 2x = -4 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
2 + 2x + -3x = -4 + 3x + -3x

Combine like terms: 2x + -3x = -1x
2 + -1x = -4 + 3x + -3x

Combine like terms: 3x + -3x = 0
2 + -1x = -4 + 0
2 + -1x = -4

Add '-2' to each side of the equation.
2 + -2 + -1x = -4 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = -4 + -2
-1x = -4 + -2

Combine like terms: -4 + -2 = -6
-1x = -6

Divide each side by '-1'.
x = 6

Simplifying
x = 6

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