2(x+1)=6(3x-5)

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Solution for 2(x+1)=6(3x-5) equation: 



2(x+1)=6(3x-5)

We move all terms to the left:

2(x+1)-(6(3x-5))=0

We multiply parentheses

2x-(6(3x-5))+2=0



We calculate terms in parentheses: -(6(3x-5)), so:

6(3x-5)

We multiply parentheses

18x-30

Back to the equation:

-(18x-30)



We get rid of parentheses

2x-18x+30+2=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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