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2(x+1)=6(3x-5)
We move all terms to the left:
2(x+1)-(6(3x-5))=0
We multiply parentheses
2x-(6(3x-5))+2=0
We calculate terms in parentheses: -(6(3x-5)), so:We get rid of parentheses
6(3x-5)
We multiply parentheses
18x-30
Back to the equation:
-(18x-30)
2x-18x+30+2=0
We add all the numbers together, and all the variables
-16x+32=0
We move all terms containing x to the left, all other terms to the right
-16x=-32
x=-32/-16
x=+2
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