2(x+1)=8(x-3)-10

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Solution for 2(x+1)=8(x-3)-10 equation: 


Simplifying
2(x + 1) = 8(x + -3) + -10

Reorder the terms:
2(1 + x) = 8(x + -3) + -10
(1 * 2 + x * 2) = 8(x + -3) + -10
(2 + 2x) = 8(x + -3) + -10

Reorder the terms:
2 + 2x = 8(-3 + x) + -10
2 + 2x = (-3 * 8 + x * 8) + -10
2 + 2x = (-24 + 8x) + -10

Reorder the terms:
2 + 2x = -24 + -10 + 8x

Combine like terms: -24 + -10 = -34
2 + 2x = -34 + 8x

Solving
2 + 2x = -34 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
2 + 2x + -8x = -34 + 8x + -8x

Combine like terms: 2x + -8x = -6x
2 + -6x = -34 + 8x + -8x

Combine like terms: 8x + -8x = 0
2 + -6x = -34 + 0
2 + -6x = -34

Add '-2' to each side of the equation.
2 + -2 + -6x = -34 + -2

Combine like terms: 2 + -2 = 0
0 + -6x = -34 + -2
-6x = -34 + -2

Combine like terms: -34 + -2 = -36
-6x = -36

Divide each side by '-6'.
x = 6

Simplifying
x = 6

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