2(x+1)=x-4(x-2)

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Solution for 2(x+1)=x-4(x-2) equation: 



2(x+1)=x-4(x-2)

We move all terms to the left:

2(x+1)-(x-4(x-2))=0

We multiply parentheses

2x-(x-4(x-2))+2=0



We calculate terms in parentheses: -(x-4(x-2)), so:

x-4(x-2)

We multiply parentheses

x-4x+8

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We get rid of parentheses

2x+3x-8+2=0

We add all the numbers together, and all the variables

5x-6=0

We move all terms containing x to the left, all other terms to the right

5x=6

x=6/5

x=1+1/5

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