2(x+10)=-3(x-10)+20

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Solution for 2(x+10)=-3(x-10)+20 equation: 



2(x+10)=-3(x-10)+20

We move all terms to the left:

2(x+10)-(-3(x-10)+20)=0

We multiply parentheses

2x-(-3(x-10)+20)+20=0



We calculate terms in parentheses: -(-3(x-10)+20), so:

-3(x-10)+20

We multiply parentheses

-3x+30+20

We add all the numbers together, and all the variables

-3x+50

Back to the equation:

-(-3x+50)



We get rid of parentheses

2x+3x-50+20=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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