2(x+12)=(x+4)(4-x)

Solution for 2(x+12)=(x+4)(4-x) equation:

2(x+12)=(x+4)(4-x)

We move all terms to the left:

2(x+12)-((x+4)(4-x))=0

We add all the numbers together, and all the variables

2(x+12)-((x+4)(-1x+4))=0

We multiply parentheses

2x-((x+4)(-1x+4))+24=0

We multiply parentheses ..

-((-1x^2+4x-4x+16))+2x+24=0


We calculate terms in parentheses: -((-1x^2+4x-4x+16)), so:

(-1x^2+4x-4x+16)

We get rid of parentheses

-1x^2+4x-4x+16

We add all the numbers together, and all the variables

-1x^2+16

Back to the equation:

-(-1x^2+16)


We get rid of parentheses

1x^2+2x-16+24=0

We add all the numbers together, and all the variables

x^2+2x+8=0

a = 1; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation