2(x+12)=(x+4)(x-4)

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Solution for 2(x+12)=(x+4)(x-4) equation: 



2(x+12)=(x+4)(x-4)

We move all terms to the left:

2(x+12)-((x+4)(x-4))=0

We use the square of the difference formula

x^2+2(x+12)+16=0

We multiply parentheses

x^2+2x+24+16=0

We add all the numbers together, and all the variables

x^2+2x+40=0

a = 1; b = 2; c = +40;
Δ = b2-4ac
Δ = 22-4·1·40
Δ = -156
Delta is less than zero, so there is no solution for the equation

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