2(x+15)+3(2x-4)=4(2-x)+2x+3(x-4)

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Solution for 2(x+15)+3(2x-4)=4(2-x)+2x+3(x-4) equation: 



2(x+15)+3(2x-4)=4(2-x)+2x+3(x-4)

We move all terms to the left:

2(x+15)+3(2x-4)-(4(2-x)+2x+3(x-4))=0

We add all the numbers together, and all the variables

2(x+15)+3(2x-4)-(4(-1x+2)+2x+3(x-4))=0

We multiply parentheses

2x+6x-(4(-1x+2)+2x+3(x-4))+30-12=0



We calculate terms in parentheses: -(4(-1x+2)+2x+3(x-4)), so:

4(-1x+2)+2x+3(x-4)

We add all the numbers together, and all the variables

2x+4(-1x+2)+3(x-4)

We multiply parentheses

2x-4x+3x+8-12

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)



We add all the numbers together, and all the variables

8x-(x-4)+18=0

We get rid of parentheses

8x-x+4+18=0

We add all the numbers together, and all the variables

7x+22=0

We move all terms containing x to the left, all other terms to the right

7x=-22

x=-22/7

x=-3+1/7

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