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2(x+2(x-3))=4(2x-3)
We move all terms to the left:
2(x+2(x-3))-(4(2x-3))=0
We calculate terms in parentheses: -(4(2x-3)), so:We get rid of parentheses
4(2x-3)
We multiply parentheses
8x-12
Back to the equation:
-(8x-12)
2(x+2(x-3))-8x+12=0
We add all the numbers together, and all the variables
-8x+2(x+2(x-3))+12=0
We move all terms containing x to the left, all other terms to the right
-8x+2(x+2(x-3))=-12
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