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2(x+2)+1=6x-4(-1+x
We move all terms to the left:
2(x+2)+1-(6x-4(-1+x)=0
We add all the numbers together, and all the variables
2(x+2)-(6x-4(x-1)+1=0
We multiply parentheses
2x-(6x-4(x-1)+1+4=0
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