2(x+2)+2=-4-3(-8+4x)

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Solution for 2(x+2)+2=-4-3(-8+4x) equation: 



2(x+2)+2=-4-3(-8+4x)

We move all terms to the left:

2(x+2)+2-(-4-3(-8+4x))=0

We add all the numbers together, and all the variables

2(x+2)-(-4-3(4x-8))+2=0

We multiply parentheses

2x-(-4-3(4x-8))+4+2=0



We calculate terms in parentheses: -(-4-3(4x-8)), so:

-4-3(4x-8)

determiningTheFunctionDomain
-3(4x-8)-4

We multiply parentheses

-12x+24-4

We add all the numbers together, and all the variables

-12x+20

Back to the equation:

-(-12x+20)



We add all the numbers together, and all the variables

2x-(-12x+20)+6=0

We get rid of parentheses

2x+12x-20+6=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

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