2(x+2)+3=3(x-3)+12

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Solution for 2(x+2)+3=3(x-3)+12 equation: 



2(x+2)+3=3(x-3)+12

We move all terms to the left:

2(x+2)+3-(3(x-3)+12)=0

We multiply parentheses

2x-(3(x-3)+12)+4+3=0



We calculate terms in parentheses: -(3(x-3)+12), so:

3(x-3)+12

We multiply parentheses

3x-9+12

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

2x-(3x+3)+7=0

We get rid of parentheses

2x-3x-3+7=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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