2(x+2)+3x=2(x+1)=1

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Solution for 2(x+2)+3x=2(x+1)=1 equation: 



2(x+2)+3x=2(x+1)=1

We move all terms to the left:

2(x+2)+3x-(2(x+1))=0

We add all the numbers together, and all the variables

3x+2(x+2)-(2(x+1))=0

We multiply parentheses

3x+2x-(2(x+1))+4=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

5x-(2x+2)+4=0

We get rid of parentheses

5x-2x-2+4=0

We add all the numbers together, and all the variables

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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