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2(x+2)+4=5+(-3)+4x
We move all terms to the left:
2(x+2)+4-(5+(-3)+4x)=0
We multiply parentheses
2x-(5+(-3)+4x)+4+4=0
We calculate terms in parentheses: -(5+(-3)+4x), so:We add all the numbers together, and all the variables
5+(-3)+4x
determiningTheFunctionDomain 4x+5+(-3)
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
2x-(4x+2)+8=0
We get rid of parentheses
2x-4x-2+8=0
We add all the numbers together, and all the variables
-2x+6=0
We move all terms containing x to the left, all other terms to the right
-2x=-6
x=-6/-2
x=+3
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