2(x+2)+5(x+5)=4(x+5)+2(x-2)

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Solution for 2(x+2)+5(x+5)=4(x+5)+2(x-2) equation: 



2(x+2)+5(x+5)=4(x+5)+2(x-2)

We move all terms to the left:

2(x+2)+5(x+5)-(4(x+5)+2(x-2))=0

We multiply parentheses

2x+5x-(4(x+5)+2(x-2))+4+25=0



We calculate terms in parentheses: -(4(x+5)+2(x-2)), so:

4(x+5)+2(x-2)

We multiply parentheses

4x+2x+20-4

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We add all the numbers together, and all the variables

7x-(6x+16)+29=0

We get rid of parentheses

7x-6x-16+29=0

We add all the numbers together, and all the variables

x+13=0

We move all terms containing x to the left, all other terms to the right

x=-13

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