2(x+2)+5(x+5)=4(x-8)+3(x-2)

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Solution for 2(x+2)+5(x+5)=4(x-8)+3(x-2) equation: 



2(x+2)+5(x+5)=4(x-8)+3(x-2)

We move all terms to the left:

2(x+2)+5(x+5)-(4(x-8)+3(x-2))=0

We multiply parentheses

2x+5x-(4(x-8)+3(x-2))+4+25=0



We calculate terms in parentheses: -(4(x-8)+3(x-2)), so:

4(x-8)+3(x-2)

We multiply parentheses

4x+3x-32-6

We add all the numbers together, and all the variables

7x-38

Back to the equation:

-(7x-38)



We add all the numbers together, and all the variables

7x-(7x-38)+29=0

We get rid of parentheses

7x-7x+38+29=0

We add all the numbers together, and all the variables

67!=0

There is no solution for this equation

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