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2(x+2)+5(x+5)=4(x-9)+2(x-2)
We move all terms to the left:
2(x+2)+5(x+5)-(4(x-9)+2(x-2))=0
We multiply parentheses
2x+5x-(4(x-9)+2(x-2))+4+25=0
We calculate terms in parentheses: -(4(x-9)+2(x-2)), so:We add all the numbers together, and all the variables
4(x-9)+2(x-2)
We multiply parentheses
4x+2x-36-4
We add all the numbers together, and all the variables
6x-40
Back to the equation:
-(6x-40)
7x-(6x-40)+29=0
We get rid of parentheses
7x-6x+40+29=0
We add all the numbers together, and all the variables
x+69=0
We move all terms containing x to the left, all other terms to the right
x=-69
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