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2(x+2)+x=3(x-1)=6
We move all terms to the left:
2(x+2)+x-(3(x-1))=0
We add all the numbers together, and all the variables
x+2(x+2)-(3(x-1))=0
We multiply parentheses
x+2x-(3(x-1))+4=0
We calculate terms in parentheses: -(3(x-1)), so:We add all the numbers together, and all the variables
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
3x-(3x-3)+4=0
We get rid of parentheses
3x-3x+3+4=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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