2(x+2)+x=5+4(x-2)

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Solution for 2(x+2)+x=5+4(x-2) equation:



2(x+2)+x=5+4(x-2)
We move all terms to the left:
2(x+2)+x-(5+4(x-2))=0
We add all the numbers together, and all the variables
x+2(x+2)-(5+4(x-2))=0
We multiply parentheses
x+2x-(5+4(x-2))+4=0
We calculate terms in parentheses: -(5+4(x-2)), so:
5+4(x-2)
determiningTheFunctionDomain 4(x-2)+5
We multiply parentheses
4x-8+5
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
We add all the numbers together, and all the variables
3x-(4x-3)+4=0
We get rid of parentheses
3x-4x+3+4=0
We add all the numbers together, and all the variables
-1x+7=0
We move all terms containing x to the left, all other terms to the right
-x=-7
x=-7/-1
x=+7

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