2(x+2)+x=5+4(x-2)

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Solution for 2(x+2)+x=5+4(x-2) equation: 



2(x+2)+x=5+4(x-2)

We move all terms to the left:

2(x+2)+x-(5+4(x-2))=0

We add all the numbers together, and all the variables

x+2(x+2)-(5+4(x-2))=0

We multiply parentheses

x+2x-(5+4(x-2))+4=0



We calculate terms in parentheses: -(5+4(x-2)), so:

5+4(x-2)

determiningTheFunctionDomain
4(x-2)+5

We multiply parentheses

4x-8+5

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

3x-(4x-3)+4=0

We get rid of parentheses

3x-4x+3+4=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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