2(x+2)-(3x+3)=5(2x+2)-20

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Solution for 2(x+2)-(3x+3)=5(2x+2)-20 equation: 



2(x+2)-(3x+3)=5(2x+2)-20

We move all terms to the left:

2(x+2)-(3x+3)-(5(2x+2)-20)=0

We multiply parentheses

2x-(3x+3)-(5(2x+2)-20)+4=0

We get rid of parentheses

2x-3x-(5(2x+2)-20)-3+4=0



We calculate terms in parentheses: -(5(2x+2)-20), so:

5(2x+2)-20

We multiply parentheses

10x+10-20

We add all the numbers together, and all the variables

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

-1x-(10x-10)+1=0

We get rid of parentheses

-1x-10x+10+1=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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