2(x+2)-(x+1)=8

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Solution for 2(x+2)-(x+1)=8 equation:


Simplifying
2(x + 2) + -1(x + 1) = 8

Reorder the terms:
2(2 + x) + -1(x + 1) = 8
(2 * 2 + x * 2) + -1(x + 1) = 8
(4 + 2x) + -1(x + 1) = 8

Reorder the terms:
4 + 2x + -1(1 + x) = 8
4 + 2x + (1 * -1 + x * -1) = 8
4 + 2x + (-1 + -1x) = 8

Reorder the terms:
4 + -1 + 2x + -1x = 8

Combine like terms: 4 + -1 = 3
3 + 2x + -1x = 8

Combine like terms: 2x + -1x = 1x
3 + 1x = 8

Solving
3 + 1x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1x = 8 + -3

Combine like terms: 3 + -3 = 0
0 + 1x = 8 + -3
1x = 8 + -3

Combine like terms: 8 + -3 = 5
1x = 5

Divide each side by '1'.
x = 5

Simplifying
x = 5

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