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2(x+2)-2=6(x+1)-4x
We move all terms to the left:
2(x+2)-2-(6(x+1)-4x)=0
We multiply parentheses
2x-(6(x+1)-4x)+4-2=0
We calculate terms in parentheses: -(6(x+1)-4x), so:We add all the numbers together, and all the variables
6(x+1)-4x
We add all the numbers together, and all the variables
-4x+6(x+1)
We multiply parentheses
-4x+6x+6
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
2x-(2x+6)+2=0
We get rid of parentheses
2x-2x-6+2=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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