2(x+2)-3(5-x)=x+5(x-3)

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Solution for 2(x+2)-3(5-x)=x+5(x-3) equation: 



2(x+2)-3(5-x)=x+5(x-3)

We move all terms to the left:

2(x+2)-3(5-x)-(x+5(x-3))=0

We add all the numbers together, and all the variables

2(x+2)-3(-1x+5)-(x+5(x-3))=0

We multiply parentheses

2x+3x-(x+5(x-3))+4-15=0



We calculate terms in parentheses: -(x+5(x-3)), so:

x+5(x-3)

We multiply parentheses

x+5x-15

We add all the numbers together, and all the variables

6x-15

Back to the equation:

-(6x-15)



We add all the numbers together, and all the variables

5x-(6x-15)-11=0

We get rid of parentheses

5x-6x+15-11=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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