2(x+2)-3(x-1)+8=3x-1

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Solution for 2(x+2)-3(x-1)+8=3x-1 equation:



2(x+2)-3(x-1)+8=3x-1
We move all terms to the left:
2(x+2)-3(x-1)+8-(3x-1)=0
We multiply parentheses
2x-3x-(3x-1)+4+3+8=0
We get rid of parentheses
2x-3x-3x+1+4+3+8=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4

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