2(x+2)-3+7x=22-6(4-x)+3x

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Solution for 2(x+2)-3+7x=22-6(4-x)+3x equation: 



2(x+2)-3+7x=22-6(4-x)+3x

We move all terms to the left:

2(x+2)-3+7x-(22-6(4-x)+3x)=0

We add all the numbers together, and all the variables

2(x+2)+7x-(22-6(-1x+4)+3x)-3=0

We add all the numbers together, and all the variables

7x+2(x+2)-(22-6(-1x+4)+3x)-3=0

We multiply parentheses

7x+2x-(22-6(-1x+4)+3x)+4-3=0



We calculate terms in parentheses: -(22-6(-1x+4)+3x), so:

22-6(-1x+4)+3x

determiningTheFunctionDomain
-6(-1x+4)+3x+22

We add all the numbers together, and all the variables

3x-6(-1x+4)+22

We multiply parentheses

3x+6x-24+22

We add all the numbers together, and all the variables

9x-2

Back to the equation:

-(9x-2)



We add all the numbers together, and all the variables

9x-(9x-2)+1=0

We get rid of parentheses

9x-9x+2+1=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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