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2(x+2)-4=4x-2(-1+x)
We move all terms to the left:
2(x+2)-4-(4x-2(-1+x))=0
We add all the numbers together, and all the variables
2(x+2)-(4x-2(x-1))-4=0
We multiply parentheses
2x-(4x-2(x-1))+4-4=0
We calculate terms in parentheses: -(4x-2(x-1)), so:We add all the numbers together, and all the variables
4x-2(x-1)
We multiply parentheses
4x-2x+2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
2x-(2x+2)=0
We get rid of parentheses
2x-2x-2=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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