2(x+2)-5(x-5)=4(x-8)-2(x-2)

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Solution for 2(x+2)-5(x-5)=4(x-8)-2(x-2) equation: 



2(x+2)-5(x-5)=4(x-8)-2(x-2)

We move all terms to the left:

2(x+2)-5(x-5)-(4(x-8)-2(x-2))=0

We multiply parentheses

2x-5x-(4(x-8)-2(x-2))+4+25=0



We calculate terms in parentheses: -(4(x-8)-2(x-2)), so:

4(x-8)-2(x-2)

We multiply parentheses

4x-2x-32+4

We add all the numbers together, and all the variables

2x-28

Back to the equation:

-(2x-28)



We add all the numbers together, and all the variables

-3x-(2x-28)+29=0

We get rid of parentheses

-3x-2x+28+29=0

We add all the numbers together, and all the variables

-5x+57=0

We move all terms containing x to the left, all other terms to the right

-5x=-57

x=-57/-5

x=11+2/5

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