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2(x+2)-6=-3(2x+1)
We move all terms to the left:
2(x+2)-6-(-3(2x+1))=0
We multiply parentheses
2x-(-3(2x+1))+4-6=0
We calculate terms in parentheses: -(-3(2x+1)), so:We add all the numbers together, and all the variables
-3(2x+1)
We multiply parentheses
-6x-3
Back to the equation:
-(-6x-3)
2x-(-6x-3)-2=0
We get rid of parentheses
2x+6x+3-2=0
We add all the numbers together, and all the variables
8x+1=0
We move all terms containing x to the left, all other terms to the right
8x=-1
x=-1/8
x=-1/8
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