2(x+2)-6=10-3(x+1)

Solution for 2(x+2)-6=10-3(x+1) equation:

2(x+2)-6=10-3(x+1)

We move all terms to the left:

2(x+2)-6-(10-3(x+1))=0

We multiply parentheses

2x-(10-3(x+1))+4-6=0


We calculate terms in parentheses: -(10-3(x+1)), so:

10-3(x+1)

determiningTheFunctionDomain
-3(x+1)+10

We multiply parentheses

-3x-3+10

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)


We add all the numbers together, and all the variables

2x-(-3x+7)-2=0

We get rid of parentheses

2x+3x-7-2=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5