2(x+2)/3=4(x+1)/4

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Solution for 2(x+2)/3=4(x+1)/4 equation: 



2(x+2)/3=4(x+1)/4

We move all terms to the left:

2(x+2)/3-(4(x+1)/4)=0

We calculate fractions


2x/()+(-(4(x+1)*3)/()=0



We calculate terms in parentheses: +(-(4(x+1)*3)/(), so:

-(4(x+1)*3)/(

We multiply all the terms by the denominator


-(4(x+1)*3)



We calculate terms in parentheses: -(4(x+1)*3), so:

4(x+1)*3

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

-12x-12

Back to the equation:

+(-12x-12)



We get rid of parentheses

2x/()-12x-12=0

We multiply all the terms by the denominator


2x-12x*()-12*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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