2(x+2)/6+3(x-2)3/6-(6x-1)2/6=x.6+7/6

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Solution for 2(x+2)/6+3(x-2)3/6-(6x-1)2/6=x.6+7/6 equation: 



2(x+2)/6+3(x-2)3/6-(6x-1)2/6=x.6+7/6

We move all terms to the left:

2(x+2)/6+3(x-2)3/6-(6x-1)2/6-(x.6+7/6)=0

We add all the numbers together, and all the variables

2(x+2)/6+3(x-2)3/6-(6x-1)2/6-(+x.6+7/6)=0

We get rid of parentheses

2(x+2)/6+3(x-2)3/6-(6x-1)2/6-x.6-7/6=0

We multiply all the terms by the denominator


2(x+2)+3(x-2)3-(6x-1)2-(x.6)*6-7=0

We add all the numbers together, and all the variables

2(x+2)+3(x-2)3-(6x-1)2-(+x.6)*6-7=0

We multiply parentheses

2x+9x-12x-6x+4-18+2-7=0

We add all the numbers together, and all the variables

-7x-19=0

We move all terms containing x to the left, all other terms to the right

-7x=19

x=19/-7

x=-2+5/7

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